Group the intermembrane space, diffuses over the inner

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Last updated: June 3, 2019

Group I2: Sara Rydeholm,Peter Enberg5/12- 2017  Cell respiration1.       When the culture medium (Cm) wasadded to the Clark reaction vessel the graph displayed a straight linear graphand the oxygen concentration was constant. When the solution of blood cells wasadded the oxygen, level began to decrease.

After DNP was added the oxygenconcentration proceeded to decrease more rapidly and the graph subsequentlybecame steeper. When KCN was added the graph became linear and the oxygen-concentrationremained constant.2.       SR1   3.       2,4-DNP is a fat-soluble moleculewhich consequently can diffuse over the membrane of cell organelles. In themitochondria, 2,4-DNP binds hydrogen in the intermembrane space, diffuses overthe inner membrane to the matrix of the mitochondria. This causes a decrease in the proton gradientover the membrane necessary for electron transport and ATP-synthase.

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Moreover,the electron transports chains effectiveness will decline which means the rateof electrons transported will decrease. This causes less ATP to be generated, insteadmore energy will be released as heat. SR2 When the mitochondria are exposed to KCN the cyanide will react with the ironin the hem-group of the cytochrome c which is responsible for the electron transportfrom complex 3 to complex 4. This causes a blockage in the electron transportchain. This consequently stops the transportation of electrons and ATP cannotbe produced.

4.       When 2,4-DNP is present in the humanbody, the rate and effectiveness of the electron transport chain will declinemeaning fewer ATP molecules will be generated. The cells compensate this lackof energy by burning more alternative energy sources, such as fat. The energylost in the electron transport chain will instead be released as heat, raisingthe body temperature and further increasing the metabolism. This is why 2,4-DNPcan be used as a weigh loss drug. 5.       The blood was diluted with a factorof 200 and was applied on a cell counting chamber.

Then the cells were counted usinga microscope. 4 large squares were inspected and the number of white bloodcells was 33, 33, 30 and 29. Moreover, each large square had an average of 31,5 cells and a volume of0,1 µl.

Per milliliter the cell count would therefore be 31.25 times10 000, which equals 312 500 white blood cells per ml. When takinginto account the dilution factor of 200 the total cell count per ml undilutedsolution will be 312 500 times 200, which equals 62 500 000white blood cells per ml. SR1Concentrationfelstavat. SR2Saknasdet inte en del info här? (KCN ser bra ut.)

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