Hydrated CompoundsA hydrated ionic compound is an ionic compound that has a well-defined amount of water trapped within the crystalline solid. The water associated with the compound is called the water of hydration.
A hydrated compound formula includes the term *nH20, where n is the number of moles of water incorporated into the solid per mole of ionic compound. Prefixes are used in naming hydrated compounds to indicate the number of waters of hydration. Many solids used in the laboratory are hydrated.
For example, reagent-grade copper(ll) sulfate is usually provided as the hydrated compound CuS04*5H20, copper(ll) sulfate pentahydrate. Some common hydrated compounds and their uses are shown in Table 3.2.1. Notice that the molar mass of a ydrated compound includes the mass of the water of hydration.Table 3.2.
1 : Some Common Hydrated Ionic Compounds Molecular formula Name Molar mass (g/mol) Common Name Uses Na2C0310H20 Sodium carbonate decahydrate Washing soda Water softener Na2S2035H20 Sodium thiosulfate pentahydrate 248. 18 Hypo Photography MgS04*7H20 Magnesium sulfate heptahydrate 246. 47 Epsom salt Dyeing and tanning cas04QH20 Calcium sulfate dihydrate 172. 17 Gypsum Wallboard caS04*hH20 Calcium sulfate hemihydrate 145. 15 Plaster of Paris Casts, molds CUSO+5H20 Copper (ll) sulfate pentahydrate 249. 8 Blue vitriol Algicide, root killer Heating a hydrated compound releases the water in the crystalline solid.
For example, heating the compound CuC12*2H20 releases two moles of water (in the form of water vapor) per mole of hydrated compound. As shown in the following example problem, we can determine the formula of a hydrated compound by performing this experiment in the laboratory.Example Problem: Determine the formula of a hydrated compound. A 32.
86 g sample of a hydrate of CoC12 was heated thoroughly in a porcelain crucible until its weight remained constant. After heating, 17. 3 g of the dehydrated compound remained in the crucible. What is the formula of the hydrate? You are asked to determine the formula of an ionic hydrated compound. You are given the mass of the hydrated compound and the mass of the compound when it has been dehydrated. First, determine the mass of water lost when the hydrated compound was heated. 32.
86 g- 17. 93 g = 14. 93 g H20 Next, calculate moles of water and moles of the dehydrated compound.
compound. The chemical formula for the hydrated compound is CoC12*6H20. 3.
2. 5T: Tutorial Assignment Due: 1/1/20 11:59 PM Score: O 3. 2. 5: Mastery Assignment Experiment 10 HydratesPRIOR READINGBe sure to read and understand the material in chapters 2 (page 68), section 2. 2, and the mole concept in chapter 3.
INTRODUCTIONHydrates are crystalline solids that contain a fixed number of water molecules as an integral part of their crystalline structure. The number of water molecules bound per metal ion is often characteristic of that particular metal ion. One of the more common hydrates is copper(ll) sulfate pentahydrate, which contains 5 moles of water per 1 mol of copper(ll) sulfate, written as CuS0405H20. It is used as a catalytic precursor, fungicide, and as a source of copper in chemical manufacturing processes.Epsom salt is magnesium sulfate heptahydrate, MgS0407H20. Epsom salt is used to reduce inflammation when applied externally. Many hydrates can be transformed to the anhydrous compound when heated strongly. For example, copper sulfate pentahydrate can be converted into anhydrous copper sulfate.
This change can be followed visually. The blue crystalline copper sulfate pentahydrate is converted when heated to a white, powdery, anhydrous salt, according to: CuS0405 H20 CUS04 + 5 H20 blue white Or generally hydrated salt anhydrous salt + water vapor It is also possible to reverse the above process, as shown in the equation below:CUS04 + 5 H20 0 CUS0405 H20 white blue indicating that the blue pentahydrate is regenerated. The property of reversibility can be used to distinguish true hydrates from other compounds that produce water when heated.
Since many hydrates contain water in a stoichiometric quantity, it is possible to determine the molar ratio of water to salt. This is exactly what you will be doing in Part II of todays experiment. We will begin by heating an accurately weighed sample of the hydrate to drive out the water. The compound formed is now anhydrous.By determining the mass of the anhydrous sample and subtracting this ass from that of the hydrate, we can determine the amount of water in the original substance.
In part I of this experiment, we will look at properties of several crystalline hydrates. Some anhydrous salts are capable of becoming hydrated on exposure to the moisture in their surroundings. These salts are called hygroscopic and can be used as chemical drying agents or desiccants. Some salts are some excellent desiccants and are able to absorb so much moisture from their surroundings that they can eventually dissolve themselves. These salts are called deliquescent.MATERIALSNickel(ll) chloride hexahydrate Cobalt(ll) chloride hexahydrate Potassium aluminum sulfate dodecahydrate Porcelain crucible and lid Unknown hydrate sample for percentage determinationEXPERIMENTAL PROCEDURERecord all data and observations directly into your notebook. Part I: Properties of Hydrates 1 .
Place about 0. 1 gof the following compounds in each one test tube: CuS0405 H20, coc1206 H20, NiC1206 H20, and H20. 2. Heat each test tube gently over a Bunsen burner flame and record your observations in your notebook. 3.
After the sample has cooled, add a few drops of deionized water. What happens and what can be concluded?Part II: Formula of a Hydrate You and your partner will perform two trials of dehydration of a copper (II) sulfate hydrate. During the course of the experiment, handle the crucible and lid only with crucible tongs as shown here or as demonstrated by your instructor. Clean two crucibles with soap and water. Rinse the crucibles with distilled water and dry them with a paper towel. Check your crucible for cracks. Heating your crucible first without the hydrate. Prepare two set-ups as shown below using a clay triangle on a ring stand.
Place each crucible on a clay triangle and heat the crucibles until red hot or for five minutes.Once the heating is complete, place the crucible on a clean wire gauze and let it cool to room temperature. Determine the mass of the crucible and lid to the nearest 0. 001 g. Obtain an unknown hydrate from your Instructor. Record the number of the unknown in your notebook.
Place about 1 to 2 g (to the nearest 0. 001 g) of the precision indicated above. Place the crucible and its lid onto the clay triangle. Arrange the lid so it is slightly ajar and begin heating very gently for about five minutes. If heated too strongly, some of the sample may decompose. Beware of spattering during the heating process.If spattering occurs put the lid on the crucible and remove the flame.
Continue heating for another 10 minutes. Cover the crucible with the lid, cool to room temperature, determine the mass of the anhydrous salt in the crucible, and report it in your notebook. Repeat the heating-cooling cycle a second time, this time heating the crucible for another 5 minutes. Determine the mass of the anhydrous salt. Continue the heating-cooling cycle until two successive weighing agree within 00.
040 grams. Calculate the mass percent water in the hydrate based upon the mass of the hydrate and that of the anhydrous salt. Then determine the molar composition of the unknown compound.WASTE DISPOSALDispose of any used and unused chemicals in the proper waste container located in the hood. Solids are placed in the container labeled “Solid Waste” and all other solutions in the beaker.
Prelaboratory Assignment: Hydrates 1. In an experiment, 2. 3754 g of copper(ll) sulfate pentahydrate is heated to drive off all the water of crystallization.
a) Write a balanced equation. b) Determine the mass of anhydrous salt that remains. Show your calculations.
2. Cobalt (II) chloride is commonly obtained from chemical supply houses as a hydrate with the formula CoC12 6H20.What is the percent water by weight in this hydrate?3. A hydrate of sodium phosphate, Na3P04, contains 49. 7% water by weight.a) How many grams of water and how many grams of anhydrous Na3P04 are in 1000.
grams of this sample?b) In this same 1000. -gram sample, how many moles of water and how many moles of anhydrous Na3P04, are present?c) What is the formula of the hydrate?Data and Analysis:HydratesPart l: Properties of HydratesRecord and analyze any observations . Create a chart and list any observations (color, appearance before and after heating, etc. ) Distinguish between the two terms absorbed and hydrated water. Explain how do you would test a colorless crystalline compound to determine if it was a hydrate?Part II: Formula of a HydrateCompare data with your partner and discuss any discrepancies and deviations in our results and observations. How would the following observations influence the percent by weight of water in the original salt mixture? Will your value be too large, too small, or not affected? Please explain your answer.a) Your anhydrous substance was slightly warm when you weighed it.b) You did not heat long enough and the hydrate was not completely converted to the anhydrous substance.
ObjectivesInvestigation of the properties of hydratesDetermination of the number moles of water of hydration in a hydrate Background Water, the most common chemical on earth, can be found in the atmosphere as water vapor. Some chemicals, when exposed to water in the atmosphere, will reversibly either adsorb it onto their surface or include it in their structure forming a complex in which water generally bonds with the cation in ionic substances. The water present in the latter case is called water of hydration or water of crystallization.
Common examples of minerals that exist as hydrates are gypsum (CaS04*2H20),Borax (Na3B407*10H20) and Epsom salts (MgS04*7H20). Hydrates generally contain water in stoichiometric amounts; hydrates’ formulae are represented using the formula of the anhydrous (non-water) component of the complex followed by a dot then the water (H20) preceded by a number corresponding to the ratio of H20 moles per mole of the anhydrous component present. They are typically named by stating the name of the anhydrous component followed by the Greek prefix specifying the number of moles of water present then the word hydrate (example: MgS04*7H20: magnesium sulfate heptahydrate).Properties of Hydrates It is generally possible to remove the water of hydration by heating the hydrate. Le Chatelier’s principle predicts that an addition of heat to an endothermic reaction (heat is a “reactant”) will shift the reaction to the right (product side). Heating will shift the equation of dehydration below to the right since it is an endothermic reaction. The residue obtained after heating, called the anhydrous compound, will have a different structure and texture and may have a different color than the hydrate. Example: CuS04*5H20 (s) cus04 (S) 5 H20 (g) deep blue ashy white 4210 H CUS04 (aq)Chapter 3: Stoichiometry 3: Stoichiometry 5: Thermochemistry 8: Covalent Bonding and Molecular Structure 15: Chemical Equilibrium 16: Acids and Bases 3.2 Stoichiometry and Compound Formulas 3.1 The Mole and Molar Mass 3.3 Stoichiometry and Chemical Reactions 3.4 Stoichiometry and Limiting Reactants 3.5 Chemical Analysis Chapter Summary Chapter Summary Assignment Reference Tools Periodic Table Molarity Calculator Molar Mass Calculator Unit Converter Thermodynamic Data 3.2e